Mathématiques

Question

quelques equations merci
4x+1=-9
-6x-1=3x-5
7x-(2x+5)=2

B=(6-b)(8b-1)
c=(3a+2)(5a-3)
D=(9c+2)(-4b-3)

2 Réponse

  • 4x+1=-9
    4x = -10
    x = -5/2

    -6x-1=3x-5
    -1+5 = 3x+6x
    4=9x
    x=4/9
    x=2/3

    7x-(2x+5)=2
    7x-2x-5=2
    5x = 7
    x = 7/5

    B=(6-b)(8b-1)
    =48b-6-8b²+b
    = -8b² + 49b - 6

    c=(3a+2)(5a-3)
    = 15a²-9a+10a-6
    = 15a² + a - 6

    D=(9c+2)(-4b-3)

    = -36bc - 27c - 8b - 6
  • 4x + 1 = - 9
    4x = - 9 - 1
    4x = - 10
    x = -10/4
    x = - 2,5

    -6x - 1 = 3x - 5
    - 6x - 3x = - 5 + 1
    - 9x = - 4
    x = 4/9

    7x - (2x + 5) = 2
    7x - 2x - 5 = 2
    7x - 2x = 2 + 5
    5x = 3
    x = 3/5
    x = 0,6

    B = (6 - b) (8b - 1)
    B = 48b - 6 - 8b² + b
    B = - 8b² + 49b - 6

    c = (3a + 2) (5a - 3)
    c = 15a² - 9a + 10a - 6
    c = 15a² + a - 6

    D = (9c + 2) (-4b - 3)
    D = - 36bc - 27c - 8b - 6

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