Exercice n 6 et 7 s'il vous plait je dois le rendre pour vendredi

exercice 7 :
[tex]A = 2(3x+4)-5(1-2x)\\ A = 6x+8-5+10x\\ \boxed{A = 16x+3}\\\\ B = 7(2x-3)+12\\ B = 14x-21+12\\ \boxed{B = 14x-9}\\\\ A = B\\16x+3=14x-9\\2x = -12\\\boxed{x = \frac{-12}{2} =-6}[/tex]

exercice 8 :
[tex] \frac{x+3}{2}= \frac{1-2x}{3}\\\\ \frac{x+3}{2}\times 2\times3= \frac{1-2x}{3}\times 2\times3\\\\ \boxed{(x+3)\times 3 = 2\times (1-2x)}\\\\ 3x+9 = 2-4x\\ 7x = -7\\ \boxed{x = \frac{-7}{7} = -1 }[/tex]