Resoudre les equations : 2)  5(x+7)-(x-4) = 19 3) [tex] \frac{4x-4}{6} [/tex]=[tex] \frac{2x}{5} [/tex]

5x+35-x+4=19
4x+39=19
4x=-20
x=-5

(4x-4)/6=2x/5

(4x-4)*5=2x*6
20x-20=12x
20x-12x=20
8x=20
x=20/8
x=5/2

Bonsoir,

[tex]2)\ 5(x+7)-(x-4) = 19\\5\times x+5\times7 - x + 4 = 19\\5x+35-x+4=19\\4x+39=19\\4x=19-39\\4x=-20\\\\x=\dfrac{-20}{4}\\\\\boxed{x=-5}[/tex]

[tex]3)\ \dfrac{4x-4}{6} = \dfrac{2x}{5}\\\\5\times(4x-4)=6\times2x\\20x-20=12x\\20x-12x=20\\8x=20\\\\x=\dfrac{20}{8}\\\\x=\dfrac{20:4}{8:4}\\\\\boxed{x=\dfrac{5}{2}}[/tex]