Mathématiques

Question


Factorise les expressions suivantes :
A = (x+3) (x + 5)-3 (x + 5):
B = (2x + 3) (x - 4) + (3 x – 5) (x – 4)
C = (3 x - 1) (x - 2) - (2 x + 5) (3x - 1)
D = x (2 x + 3) - 7 (2 x + 3)
svp aidez-moi merci ! ​

2 Réponse

  • Réponse:

    A=x(x+5)

    B=(x-4)(5x-2)

    C= (3x-1)(-x-7)

    D=(2x+3)(x-7)

    Explications étape par étape:

    1. (x+3)(x+5)-3(x+5)=

    (x+5)(x+3-3)

    (x+5)(×)

    x(x+5)

    (2x+3)(x-4)+(3x-5)(x-4)

    (x-4)(2x+3+3x-5)

    (x-4)(5x-2)

    C=(3x-1)(x-2-2x-5)

    (3x-1)(-x-7)

    D=x(2x+3)-7(2x+3)

    (2x+3)(x-7)

  • Salut

    [tex]\rule{7cm}{1mm}[/tex]

    A = (x + 3) (x + 5) -3 (x + 5)

    A = (x + 5)[(x + 3) - 3]

    A = (x + 5)(x + 3 - 3)

    A = (x + 5)(x)

    B = (2x + 3) (x - 4) + (3x - 5) (x - 4)

    B = (x - 4)[(2x + 3) + (3x - 5)]

    B = (x - 4)(2x + 3 + 3x - 5)

    B = (x - 4)(5x - 2)

    C = (3x - 1) (x - 2) - (2x + 5) (3x - 1)

    C = (3x - 1)[(x - 2) - (2x + 5)]

    C = (3x - 1)(x - 2 - 2x - 5)

    C = (3x - 1)(-x - 7)

    D = x(2x + 3) - 7(2x + 3)

    D = (2x + 3)(x - 7)

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